model 3 successive discount Practice Questions Answers Test with Solutions & More Shortcuts
discount PRACTICE TEST [4 - EXERCISES]
model 1 profit x after discount y
model 2 hiking & discounting
model 3 successive discount
model 4 mixed discount problems of marked price
Question : 11 [SSC CGL Prelim 2007]
An article listed at Rs.800 is sold at successive discounts of 25% and 15%. The buyer desires to sell it off at a profit of 20% after allowing a 10% discount. What would be his list price ?
a) Rs.680
b) Rs.640
c) Rs.620
d) Rs.600
Answer »Answer: (a)
Using Rule 5,
Effective discount
= 25 + 15 - ${25 × 15}/100$
= 40 - 3.75 = 36.25 %
CP for buyer
= (100 - 36.25) % of 800
= ${63.75 × 800}/100$ = Rs.510
To gain 20%,
SP = Rs.$({120 × 510}/100)$ = Rs.612
Let the list price be Rs.x.
90% of x = Rs.612
${90x}/100$ = 612
$x = 61200/90$ = Rs.680
Question : 12
The marked price of watch was Rs.820. A man bought the watch for Rs.570.72 after getting two successive discounts, of which the first was 20%. The second discount was
a) 11%
b) 13%
c) 18%
d) 15%
Answer »Answer: (b)
Total discount
=Rs.(820 - 570.72) = Rs.249.28
First discount = $820 × 20/100$ = Rs.164
Second discount
= Rs.(249.28 - 164) = Rs.85.28
Price of the article after first discount
= Rs.(820 - 164) = Rs.656
If the second discount be x% , then
x% of 656 = 85.28
$x = {85.28 × 100}/656 = 13%$
Using Rule 3,
Here, M.P. = Rs.820, S.P. = 570.72, $D_1 = 20%, D_2$ = ?
S.P. = M.P.$({100 - D_1}/100)({100 - D_2}/100)$
$570.72 = 820 ({100 - 20}/100)({100 - D_2}/100)$
$5707200/{820 × 80} = 100 - D_2$
$100 - D_2 = 87 ⇒ D_2$ = 13%
Question : 13
An article is listed at Rs.900 and two successive discounts of 8% and 8% are given on it. How much would the seller gain or lose, if he gives a single discount of 16%, instead of two discounts ?
a) Loss of Rs.4.76
b) Gain of Rs.5.76
c) Gain of Rs.4.76
d) Loss of Rs.5.76
Answer »Answer: (d)
Using Rule 5,
Equivalent discount for two successive discounts of 8% and 8%
= $(8 + 8 - {8 × 8}/100)$%
= (16–0.64) % = 15.36 %
SP = (100 –15.36) % of 900
= Rs.$({84.64 × 900}/100)$ = Rs.761.76
For a single discount of 16%,
SP = 84% of 900
= Rs.$({84 × 900}/100)$ = Rs.756
Certainly seller will lose in this case.
Loss = Rs. (761.76 - 756) = Rs.5.76
Question : 14
The marked price of a T.V. is Rs.16,000. After two successive discounts it is sold for Rs.11,400. If the first discount is 5%, then the rate of second discount is
a) 25%
b) 30%
c) 15%
d) 20%
Answer »Answer: (a)
After a discount of 5%
SP = ${95 × 16000}/100$ = Rs.15200
Let the second discount be x%.
x% of 15200 = (15200 - 11400)
${x × 15200}/100 = 3800$
$x = {3800 × 100}/15200 = 25$
Second discount = 25%
Using Rule 3,
Here, M.P. = 16000, S.P. = 11400, $D_1 = 5%, D_2$ = ?
S.P. = M.P.$({100 - D_1}/100)({100 - D_2}/100)$
11400 = 16000$({100 - 5}/100)({100 - D_2}/100)$
$114000/{16 × 95} = 100 - D_2$
$75 = 100 - D_2 ⇒ D_2$ = 25%
Question : 15 [SSC SO 2006]
A shopkeeper gives two successive discounts on an article marked Rs.450. The first discount given is 10 per cent. If the customer pays Rs.344.25 for the article, the second discount given is
a) 15 per cent
b) 12 per cent
c) 14 per cent
d) 10 per cent
Answer »Answer: (a)
Let the second discount be x per cent.
According to the question,
$450 × {100 - 10}/100 × {100 - x}/100$ = 344.25
100 - x = ${344.25 × 100 × 100}/{450 × 90}$
100 - x = 85
x = 100 - 85 = 15%.
Using Rule 3,
Here, M.P. = Rs.450, S.P. = Rs.344.25, $D_1 = 10%, D_2$ = ?
S.P. = M.P.$({100 - D_1}/100)({100 - D_2}/100)$
$344.25 = 450 × ({100 - 10}/100)({100 - D_2}/100)$
$3442500/{450 × 90} = (100 - D_2)$
$85 = 100 - D_2 ⇒ D_2$ = 15%
IMPORTANT quantitative aptitude EXERCISES
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